Synthetic division, the Remainder Theorem and the Factor Theorem
A fast shortcut for dividing a polynomial by x − c, how to find a remainder without dividing at all, and how to tell whether x − c is a factor.
A shortcut for one common case
Long division always works, but it's slow. When the divisor has the form \(x - c\), a linear binomial whose leading coefficient is 1, there's a much faster method: synthetic division. It keeps only the numbers and drops the variables.
Divisors like \(x - 4\),\(x + 1\) (which is \(x - (-1)\)) or \(x - \frac{2}{3}\) all qualify. The number \(c\) is the value that makes the divisor zero: for \(x + 1\),\(c = -1\).
How it works
Let's redo a division from the previous lesson, \((3x^3 - 5x^2 + 4x - 7) \div (x - 2)\), where \(c = 2\).
The Remainder Theorem
There's an even faster way to get the remainder: don't divide at all.
Why? By the definition of division, \(P(x) = (x - c)\,Q(x) + R\). Plug in \(x = c\): the first part becomes \(0 \cdot Q(c) = 0\), which leaves \(P(c) = R\).
The Factor Theorem
The Remainder Theorem has an immediate consequence, and it's one of the most useful facts in algebra.
A number \(c\) with \(P(c) = 0\) is called a zero (or root) of the polynomial. Finding a zero hands you a linear factor, which is exactly what you need to factor higher-degree polynomials.
You don't have to guess zeros at random.
Practice
Quick check
To divide by \(x + 7\) synthetically, which value of \(c\) do you use?
\(x + 7 = x - (-7)\), so \(c = -7\), the value that makes the divisor zero.
Quick check
What is the remainder of \((x^4 - 3x + 1) \div (x - 1)\)?
By the Remainder Theorem: \(P(1) = 1 - 3 + 1 = -1\).
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