Lesson 12 of 16, 15 min read
Solving quadratic equations
Standard form, solving by square roots, by factoring and by completing the square, the quadratic formula and what the discriminant tells you.
Standard form
A quadratic equation is one that can be written in standard form
If \(a\) were \(0\), the equation would be linear. A quadratic equation has at most two real solutions, also called roots.
There are four main ways to solve one. The first three are shortcuts for special cases; the fourth always works.
Method 1: square roots
When there's no \(x\) term (\(b = 0\)), isolate \(x^2\) (or a squared binomial) and take square roots. Don't forget the \(\pm\).
If isolating gives \(x^2\) equal to a negative number, as in \(x^2 = -9\), there's no real solution.
Method 2: factoring
So if the quadratic factors, set each factor equal to zero.
Method 3: completing the square
Any quadratic can be rewritten as a squared binomial plus a number. With \(a = 1\), add \(\left(\frac{b}{2}\right)^2\) to both sides.
Completing the square on the general equation \(ax^2 + bx + c = 0\) produces the quadratic formula.
Method 4: the quadratic formula
The discriminant
The expression under the square root, \(b^2 - 4ac\), is the discriminant. Its sign tells you how many real solutions there are before you finish solving.
| Discriminant \(b^2 - 4ac\) | Real solutions | Graph of \(y = ax^2 + bx + c\) |
|---|---|---|
| positive | two | crosses the \(x\)-axis twice |
| zero | one (a double root) | touches the \(x\)-axis once |
| negative | none | never meets the \(x\)-axis |
Practice
Quick check
How many real solutions does \(2x^2 - 3x + 5 = 0\) have?
The discriminant is \(9 - 40 = -31\), which is negative.
Quick check
What are the solutions of \(x^2 - 16 = 0\)?
\(x^2 = 16\), so \(x = \pm 4\).
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