Lesson 12 of 16, 15 min read

Solving quadratic equations

Standard form, solving by square roots, by factoring and by completing the square, the quadratic formula and what the discriminant tells you.

Standard form

A quadratic equation is one that can be written in standard form

\[ax^2 + bx + c = 0 \qquad \text{with } a \neq 0\]

If \(a\) were \(0\), the equation would be linear. A quadratic equation has at most two real solutions, also called roots.

There are four main ways to solve one. The first three are shortcuts for special cases; the fourth always works.

Method 1: square roots

When there's no \(x\) term (\(b = 0\)), isolate \(x^2\) (or a squared binomial) and take square roots. Don't forget the \(\pm\).

If isolating gives \(x^2\) equal to a negative number, as in \(x^2 = -9\), there's no real solution.

Method 2: factoring

So if the quadratic factors, set each factor equal to zero.

Method 3: completing the square

Any quadratic can be rewritten as a squared binomial plus a number. With \(a = 1\), add \(\left(\frac{b}{2}\right)^2\) to both sides.

Completing the square on the general equation \(ax^2 + bx + c = 0\) produces the quadratic formula.

Method 4: the quadratic formula

The discriminant

The expression under the square root, \(b^2 - 4ac\), is the discriminant. Its sign tells you how many real solutions there are before you finish solving.

Discriminant \(b^2 - 4ac\)Real solutionsGraph of \(y = ax^2 + bx + c\)
positivetwocrosses the \(x\)-axis twice
zeroone (a double root)touches the \(x\)-axis once
negativenonenever meets the \(x\)-axis

Practice

Quick check

How many real solutions does \(2x^2 - 3x + 5 = 0\) have?

Quick check

What are the solutions of \(x^2 - 16 = 0\)?

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